2sin^2x+4cos^2x+3=0

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Solution for 2sin^2x+4cos^2x+3=0 equation: 


Simplifying
2sin2x + 4cos2x + 3 = 0

Reorder the terms:
3 + 4cos2x + 2in2sx = 0

Solving
3 + 4cos2x + 2in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + 4cos2x + -3 + 2in2sx = 0 + -3

Reorder the terms:
3 + -3 + 4cos2x + 2in2sx = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 4cos2x + 2in2sx = 0 + -3
4cos2x + 2in2sx = 0 + -3

Combine like terms: 0 + -3 = -3
4cos2x + 2in2sx = -3

Add '-2in2sx' to each side of the equation.
4cos2x + 2in2sx + -2in2sx = -3 + -2in2sx

Combine like terms: 2in2sx + -2in2sx = 0
4cos2x + 0 = -3 + -2in2sx
4cos2x = -3 + -2in2sx

Divide each side by '4os2x'.
c = -0.75o-1s-2x-1 + -0.5in2o-1s-1

Simplifying
c = -0.75o-1s-2x-1 + -0.5in2o-1s-1

Reorder the terms:
c = -0.5in2o-1s-1 + -0.75o-1s-2x-1

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